H t 48t−16t2 domain
Webh(t)=-16t2+48t+4 No solutions found Rearrange: Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation : ... The height … WebMatt hot a baseball into the air with an initial upward velocity of 48 feet per sec. The height h in feet of the ball above the ground can be modeled by h= -16t^2 + 48t + 2, where t is the time in sec … read more
H t 48t−16t2 domain
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WebThe function h (t)=−16t2+48t+28 models the height (in feet) of a ball where t is the time (in seconds). What is the maximum height that the ball reaches? Just write the numerical answer - do not include h= or any units in your answer. This problem has been solved! Web20 mrt. 2024 · Explanation: Find the roots of the parabola by setting h = 0 ⇒ −16t2 +64t = 0 Factorising gives. −16t(t − 4) = 0 ⇒ t = 0 or t = 4 Since the parabola is symmetrical the axis of symmetry will pass through the maximum. The axis of symmetry is positioned at the mid- point of the roots. ⇒ t = 2 ⇒ max. height = −16(2)2 +64(2)
WebThe function h (t)=−16t2+48t+28 models the height (in feet) of a ball where t is the time (in seconds). What is the maximum height that the ball reaches? Just write the numerical … Web3 feb. 2024 · The height h of a projectile is a function of the time t it is in the air. The height in feet for t seconds is given by the function h(t) = −16t2 + 96t. What...
Webh=48t-16t2 No solutions found Rearrange: Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation : h- (48*t-16*t^2)=0 ... h(t) = … Web24 aug. 2024 · Remember the domain is the possible values of the independent variable (which in this case is "t"). If we let t = 0 and plug it into the equation we get: h (t) = -16t 2 …
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Webh(t)=-16t2+48t+4 No solutions found Rearrange: Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation : ... The height … čestitke za novorodence na makedonskiWeb48t−16t2 = h 48 t - 16 t 2 = h Subtract h h from both sides of the equation. 48t−16t2 −h = 0 48 t - 16 t 2 - h = 0 Use the quadratic formula to find the solutions. −b±√b2 −4(ac) 2a - b … čestitke za novo služboWeb14 sep. 2014 · The A model rocket is launched upward with an initial velocity of 200 feet per second. The height, in feet, of the rocket t seconds after the launch is given by h = −16t2 + 200t. How many seconds after the launch will the rocket be 380 feet above the ground? Round to the nearest tenth of a second. (Enter your answers as a comma-separated list.) cestitke za novorodjenceWebThe height h of a projectile launched from ground level is a function of the time t it is in the air. The height in feet for t seconds is given by the function h(t) = -16t2 + 48t. What is the … cestitke za nova godinaWebYou'll get a detailed solution from a subject matter expert that helps you learn core concepts. See Answer. Question: The height h, in feet, of a ball above the ground t seconds after being thrown upward with a velocity of 48 ft/s is given by h = −16t2 + 48t + 3. cestitke za novogodisnje praznikeWebThe function h (t)=−16t2+48t+288 models the height, h, of the ball above the ground as a function of time t. Find the time (s) when the ball's height is 288 feet. The ball has a height of 288feet when t= The ball hits the ground at t= Expert Solution Want to see the full answer? Check out a sample Q&A here See Solution star_border čestitke za novu godinu 2023WebThe equation h=-16t^2+64t+30 gives the height h after t seconds. Solve for both t and h. • ( 5 votes) Stanley Z. 4 years ago Maximum height h -> find the axis of symmetry -> x= -b/2a= -64/2 (-16)= 2, plug it in -> -16 (2)^2+64 (2)+30= 94, so maximum height is 94 ft. At what time will the ball reach the ground? cestitke za novu godinu